I am new to the OpenFileDialog function, but have the basics figured out. What I need to do is open a text file, read the data from the file (text only) and correctly place the data into separate text boxes in my application. Here's what I have in my 'open file' event handler:
Active1 year, 8 months ago
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I need to open the bitmap image in the window form using open file dialog (i will load it from drive).the image should fit in the picture box.here is some code i have tried but got error!
The text file I need to read is this (for homework, I need to read this exact file), It has an employee number, name, address, wage, and hours worked:
In the text file I was given, there are 4 more employees with info immediately after this in the same format. You can see that the employee wage and hours are on the same line, not a typo.
I have an employee class here:
So I need to pull the text from that file into my Employee class, then output the data to the correct textbox in the windows forms application. I am having trouble understanding how to do this right. Do I need to use a streamreader? Or is there another, better way in this instance? Thank you.
bryanmac
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xavixavi
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2 Answers
Here's one way:
Modified from here:MSDN OpenFileDialog.OpenFile
EDIT Here's another way more suited to your needs:
jordanhill123jordanhill123
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for this approach, you will need to add system.IO to your references by adding the next line of code below the other references near the top of the c# file(where the other using ****.** stand).
this next code contains 2 methods of reading the text, the first will read single lines and stores them in a string variable, the second one reads the whole text and saves it in a string variable(including 'n' (enters)) Ping info download for android.
System.windows.forms.openfiledialog
both should be quite easy to understand and use.
To split the text you can use .Split(' ') and use a loop to put the name back into one string. if you don't want to use .Split() then you could also use foreach and ad an if statement to split it where needed.
to add the data to your class you can use the constructor to add the data like:
or you can add it using the set by typing .variablename after the name of the instance(if they are public and have a set this will work). to read the data you can use the get by typing .variablename after the name of the instance(if they are public and have a get this will work).
TeD van LoonTeD van Loon
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Active1 year, 7 months ago
I'm writing a little utility that starts with selecting a file, and then I need to select a folder. I'd like to default the folder to where the selected file was.
OpenFileDialog.FileName returns the full path & filename - what I want is to obtain just the path portion (sans filename), so I can use that as the initial selected folder.
Galaxy life download for pc. Are there any .NET methods to do this, or do I need to use NightOwl888
regex, split, trim, etc??
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Windows Forms Openfiledialog FreeKevin HainesKevin Haines
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5 Answers
Use the
Path class from System.IO . It contains useful calls for manipulating file paths, including GetDirectoryName which does what you want, returning the directory portion of the file path.
Usage is simple.
Jeff YatesJeff Yates
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Jan MacháčekJan Macháček
Adi Lester
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MaxMax
You can use FolderBrowserDialog instead of FileDialog and get the path from the OK result.
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ShaahinShaahin
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AbdelAbdel
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